(5x+2)=(3x^2+4x+8)

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Solution for (5x+2)=(3x^2+4x+8) equation:


Simplifying
(5x + 2) = (3x2 + 4x + 8)

Reorder the terms:
(2 + 5x) = (3x2 + 4x + 8)

Remove parenthesis around (2 + 5x)
2 + 5x = (3x2 + 4x + 8)

Reorder the terms:
2 + 5x = (8 + 4x + 3x2)

Remove parenthesis around (8 + 4x + 3x2)
2 + 5x = 8 + 4x + 3x2

Solving
2 + 5x = 8 + 4x + 3x2

Solving for variable 'x'.

Reorder the terms:
2 + -8 + 5x + -4x + -3x2 = 8 + 4x + 3x2 + -8 + -4x + -3x2

Combine like terms: 2 + -8 = -6
-6 + 5x + -4x + -3x2 = 8 + 4x + 3x2 + -8 + -4x + -3x2

Combine like terms: 5x + -4x = 1x
-6 + 1x + -3x2 = 8 + 4x + 3x2 + -8 + -4x + -3x2

Reorder the terms:
-6 + 1x + -3x2 = 8 + -8 + 4x + -4x + 3x2 + -3x2

Combine like terms: 8 + -8 = 0
-6 + 1x + -3x2 = 0 + 4x + -4x + 3x2 + -3x2
-6 + 1x + -3x2 = 4x + -4x + 3x2 + -3x2

Combine like terms: 4x + -4x = 0
-6 + 1x + -3x2 = 0 + 3x2 + -3x2
-6 + 1x + -3x2 = 3x2 + -3x2

Combine like terms: 3x2 + -3x2 = 0
-6 + 1x + -3x2 = 0

Begin completing the square.  Divide all terms by
-3 the coefficient of the squared term: 

Divide each side by '-3'.
2 + -0.3333333333x + x2 = 0

Move the constant term to the right:

Add '-2' to each side of the equation.
2 + -0.3333333333x + -2 + x2 = 0 + -2

Reorder the terms:
2 + -2 + -0.3333333333x + x2 = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -0.3333333333x + x2 = 0 + -2
-0.3333333333x + x2 = 0 + -2

Combine like terms: 0 + -2 = -2
-0.3333333333x + x2 = -2

The x term is -0.3333333333x.  Take half its coefficient (-0.1666666667).
Square it (0.02777777779) and add it to both sides.

Add '0.02777777779' to each side of the equation.
-0.3333333333x + 0.02777777779 + x2 = -2 + 0.02777777779

Reorder the terms:
0.02777777779 + -0.3333333333x + x2 = -2 + 0.02777777779

Combine like terms: -2 + 0.02777777779 = -1.97222222221
0.02777777779 + -0.3333333333x + x2 = -1.97222222221

Factor a perfect square on the left side:
(x + -0.1666666667)(x + -0.1666666667) = -1.97222222221

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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